00:01
Okay, so if a is a matrix of order, let's say, m by n, and x is a column vector of order n by one, then the product of a times x can be expressed as a linear combination of the column vectors of a in which the coefficients are the entries of x.
00:20
So given here, we have a matrix a, so we have in the form, a, x is equal to b, right? well, we can factor out an x1, x2, and x3.
00:34
So we have x1 times our first column vector of 5 negative 1 ,0, plus x2 times our next column vector, plus x3 times our next column vector is equal to, well, the given column vector here.
00:47
That implies that 5x1 minus 1, so minus x, minus x, minus 1 times x1, so minus x1.
01:01
And then we have, well, times zero times x1.
01:06
So zero x1.
01:15
Plus 6x2, minus 2x2.
01:22
And then we have 4x2.
01:28
And then plus negative 7x3.
01:33
And then plus 3x4.
01:35
And a negative, well, negative 1 x3.
01:39
So negative x3 is equal to the given column vector of 203.
01:50
Okay.
01:54
So while we get here, we get 5x1 minus, or 5x1 plus 6x2 minus x3 is equal to 2.
02:04
And then, so, yeah, we get 5x1 plus 6x2.
02:18
Minus 7x3 is equal to the 2, right? that's what we get from right here.
02:26
We get 5x1 plus 6x2 minus 7x3 is equal to 2.
02:30
Our next equation becomes, well, negative 1x1, so that's negative x1...