00:02
Okay, we're solving this system for x and y, and so i'm going to try the addition subtraction method.
00:08
I'm going to multiply the first equation by b and the second equation by a.
00:14
So that's going to give us ab x plus a squared b y equals b and ab x plus a b squared y equals a.
00:28
And so if we subtract these equations the x terms are eliminated and we have a squared b minus a.
00:34
Minus a b squared times y equals b minus a.
00:39
So let's get y by itself.
00:41
Y is b minus a over a squared b minus a squared.
00:46
And let's see if we can reduce that.
00:48
I'm going to factor the denominator by factoring an a and a b out of both terms.
00:54
So if a b times a quantity a minus b and b are opposites.
01:00
So if we cancel them we leave a negative one.
01:02
So y is negative 1 over ab...