00:01
So we're solving the separable equation dp over d t equals p minus p squared.
00:05
So the first step with this equation is just trying to get the same variables to the same side of the equation, separating the equation.
00:14
So we're going to move all of the p's to the left hand side and we're going to move this d t to the right hand side.
00:20
So that's going to give us this new equation.
00:22
1 over p, i just factored out the p, p times 1 minus p d p d p equals d t.
00:30
Going to take the integral of this new equation.
00:33
The right hand side is pretty simple, but we're going to focus on the left hand side.
00:37
And to take this integral, we're going to have to do partial fraction decomp.
00:41
So the fraction that we're trying to decompose is 1 over p times 1 minus p.
00:51
And that's going to equal a, an unknown variable over p, plus b over 1 minus p.
00:58
So we're going to multiply the entire thing by the full denominator, p1 minus p...