Question
Solve the given differential equations by Laplace transforms. The function is subject to the given conditions.$$y^{\prime}+2 y=t e^{-2 t}, y(0)=0$$
Step 1
The Laplace transform of $y^{\prime}$ is $sY(s)-y(0)$ and the Laplace transform of $2y$ is $2Y(s)$. The Laplace transform of $te^{-2t}$ is $\frac{1}{(s+2)^2}$. Since $y(0)=0$, we have $$sY(s) + 2Y(s) = \frac{1}{(s+2)^2}.$$ Show more…
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