Solve the given initial-value problem. Write the solution as an explicit algebraic function $y=f(x)$ (see Notes From the Classroom in Section 1.3). You may have to use a trigonometric identity.
$\sqrt{1-x^{2}} \frac{d y}{d x}=\sqrt{1-y^{2}}, \quad y(0)=\frac{\sqrt{3}}{2}$