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Solve the given initial value problem.$x^{2} y^{\prime \prime}-x y^{\prime}+y=0, \quad y(1)=1, y^{\prime}(1)=1$

Calculus 3

Chapter 17

Second-Order Differential Equations

Section 4

Euler Equations

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Solve the given initial va…

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Solve the given initial-va…

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Solve the initial value pr…

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Find the solution of the i…

Hey, you Brown 27 four y F one equals one. Why prime off one equals one. So we have our squared minutes to R plus one equals zero r equals one repeated twice and therefore wise you go to see one x plus c two x l n x take the derivative and get C one plus c two Ln X plus c two. Using the initial conditions, we find that see you want us to go toe one and C two is to go to zero. So therefore, our equation, it's y equals X.

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