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Solve the given initial value problem.$x^{2} y^{\prime \prime}+3 x y^{\prime}-3 y=0, \quad y(1)=1, y^{\prime}(1)=-1$

Calculus 3

Chapter 17

Second-Order Differential Equations

Section 4

Euler Equations

Missouri State University

Campbell University

Harvey Mudd College

Idaho State University

Lectures

02:31

Solve the Initial Value Pr…

03:01

Solve the initial value pr…

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Solve the given initial-va…

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Alright, Problem number 25 for a wife, one equals one and why prime of one equals one its first. When they are form, we get R squared plus two ar minus three equals zero. So R minus one times are plus three or four articles One common negative three. So we get the form of why is gonna see one X plus C two over execute Take the derivative Get why primary will see one minus three C two over X the fourth plugging in our initial conditions. You can see you one minus three C two equals negative one and C one plus C two equals one solving for C one and C two we get the final equation. Why it goes one half x plus one half one over X que

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