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Solve the given initial value problem.$x^{2} y^{\prime \prime}+7 x y^{\prime}+9 y=0, \quad y(1)=1, y^{\prime}(1)=0$

Calculus 3

Chapter 17

Second-Order Differential Equations

Section 4

Euler Equations

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09:24

Solve the given initial-va…

01:12

Solve the given initial va…

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08:04

number 28 for a while When it goes Boylan, why prime of one equals zero. So then we get r squared plus six R plus nine equals zero articles. *** three. Repeated twice. Before we get wise, you go to see one even I get three z plus c two e to the negative three z and therefore, why is equal to see one over X Q plus c two Ln X over X cubed Why Prime is gonna *** three c one over x to the fourth plus C to one minus three Ln x So the fourth. Using the initial conditions, we find that C one equals one and C two equals three. Therefore, wise you goto one over x cubed plus three Ln x over x

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