Question
Solve the given linear system by any method.$$\begin{array}{r} 2 x-y-3 z=0 \\ -x+2 y-3 z=0 \\ x+y+4 z=0 \end{array}$$
Step 1
We can do this by adding half of row one to row two and subtracting half of row one from row three. This transforms our system into the following: $$\begin{array}{r} 2 x-y-3 z=0 \\ 0+1.5 y-3 z=0 \\ 0+1.5 y+5 z=0 \end{array}$$ Show more…
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