Question

Solve the given polynomial or rational inequality. $\frac{(x+1)(x-2)}{(x+3)}<0$

   Solve the given polynomial or rational inequality.
$\frac{(x+1)(x-2)}{(x+3)}<0$
Calculus for dummies: 1,001 calculus practice problems
Calculus for dummies: 1,001 calculus practice problems
Patrick Jones 1st Edition
Chapter 1, Problem 58 ↓
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Solve the given polynomial or rational inequality. $\frac{(x+1)(x-2)}{(x+3)}<0$
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Transcript

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00:01 Okay, suppose we have a rational inequality.
00:03 Rational means i have a denominator that i need to make sure i don't make it undefined.
00:08 And inequality means i have an inequality, so i'm considering different intervals that make this function positive or negative.
00:15 First thing i'm going to do is i'm going to look for my critical point, set the numerator and denominator equal to zero.
00:21 When i set the numerator equal to zero, i could set both terms equal to zero by the zero product property.
00:27 So x can be negative 1 or x can be positive 2.
00:31 And then setting my denominator equal to 0, i know that x can be negative 3.
00:37 So these are my three critical points.
00:39 Once i have my critical points, i can create intervals from these critical points that determine if my function will be positive or negative.
00:48 So intervals in between these critical points, i have three critical points.
00:54 So i'm going to have four intervals, starting from negative infinity to positive infinity.
00:58 On each interval, i need to pick a test point that i'm going to plug into my function.
01:05 When i plug my test point into my function, i'm ultimately determining if it's positive or negative.
01:12 Why do i care if it's positive or negative? well, because i want my function to be less than zero.
01:18 So really i want it to be below zero or negative.
01:21 Okay, to make this inequality true.
01:24 So i'm looking for the intervals there...
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