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Solve the given problems.A surveyor measures the distance between two markers to be $378.00 \mathrm{m}$. Then, moving along a line equidistant from the markers, the distance $d$ from the surveyor to each marker is $d=189.00 \csc \frac{1}{2} \theta,$ where $\theta$ is the angle between the lines of sight to the markers. See Fig. 27.6. By using differentials, find the change in $d$ if $\theta$ changes from $98.20^{\circ}$ to $98.45^{\circ}$.

Calculus 1 / AB

Chapter 27

Differentiation of Transcendental Functions

Section 2

Derivatives of the Other Trigonometric Functions

Derivatives

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for this given problem, we have a surveyor measuring the distance between two markers and then moving along the line equidistant. So we see that the distance is going to be, I'm called D. F kovacs can be 1 89 co second of one half. They don't mind escapes packs. So we want to find the change in B if they had changes from 98.2° To 98.45°.. So based on this, we see that a minor change is going to be F of 98.45 minus F of 98.2. And that's provided by 98.45 98 point Let me get about a negative 53 .71. So you see that's going to be the slope. Um And based on that, we see that negative 53.7 or negative 54 will end up being the rate of change approximately from 98.2°- 98.45°.. We want to keep in mind that this is going to be in Degrees, so in this case it will actually be about negative 1.88 as the slope, but everything else holds the same.

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