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Solve the given problems by finding the appropriate derivative.Find the equation of the line tangent to the curve of $y=x^{2} \ln x$ at the point (1,0).

$$y=x-1$$

Calculus 1 / AB

Chapter 27

Differentiation of Transcendental Functions

Section 8

Applications

Derivatives

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So we need to find the equation of the tangent line. Why? Mhm X squared I'm like At the .1 comma zero. So to find the equation of the tangent lines that are given curves, we will first find the slope of the tangent line at the given point. So if you want the just equal to X squared X. Close two x times Alan Novak. So we have to find the slope at 1:00. Therefore putting the value of the coordinates and dy dx you get the stuff of the tangent line That is equal to one because two tom's one Time time of one Best Equal to zero. So the equation of the line, the point slope form my mind is why why equal to m times ah minus except one to accept one Is equal to one. The wife of one is equal to zero And M is equal to one. From the above equation we get the equation of the tangent line Given the curve won't come to zero To be 1 0 is equal to one Times X -1. So why is equal to X -1?

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