solve-the-given-problems-by-finding-the-appropriate-derivative-the-power-supply-ptext-in-w-in-a-sate

Question

Solve the given problems by finding the appropriate derivative.
The power supply $P(	ext { in } W$ ) in a satellite is $P=100 e^{-0.005 t}$, where $t$ is measured in days. Find the time rate of change of power after 100 days.

Stanley Enemuo · Accepted Answer

So we need to find the time rate of change of power Left on 100 days in a satellite. If the power supply in the satellite this P. L. Is equal to 100 ft times each of the negative zero point 0052. Which is a number of age. Now we have to find the rate of change of power. Then we could differentiate the given power respect to time. So DP DT that is equal to negative zero coins. But time speed to the -0.0052. Now the time rate of change of power 108. We did calculate that by substitution and see Let&#x27;s see if he puts 100 into the derivative of chain right here. And then we get DP DT that&#x27;s equal to negative zero point 303. And that&#x27;s the rate of change of power after 100 days.

Joshua Eastwood · Answer

is this? Our Oakland formula and T is the time in days and it says how much powers will be available 108. So what we&#x27;re gonna do is plug in. Okay, 100 into hears. We&#x27;re gonna get negative, 100 over 250 men. All we&#x27;re gonna do is put that into our calculator, and I would encourage you to follow um, your calculator as I&#x27;m doing it. I can&#x27;t. I&#x27;m not showing you my screen. Um, because I don&#x27;t think it&#x27;s a need to necessarily. But I want you to be able to get the same number that I do. Okay, So I&#x27;m getting when I put that in my calculator 33.5. So if you can do it on yours and make sure that you also get 33.5, you know how to use your calculator properly and you&#x27;ll get threatening

Foster Wisusik · Answer

Okay. This question wants us to find the derivative of peace. So we know that DPD, too, is just the derivative with respect to t of our function, which in our case, the 50 stays out in front because it&#x27;s a constant. And then the derivative of the exponential, it&#x27;s just again e to the negative 0.60 times the derivative of that using the chain role. So the derivative of our exponents is just negative 0.6 and then simplifying we get dp DT is equal to 50 times negative 0.6 times e to the negative 0.60 or multiplying those two out we get negative 30 you to the negative 0.60 because the derivative of E to some function by the chain role is just e to that phone.

Chinmai Managoli · Answer

we have been given a battery whose power is decaying exponentially, and we&#x27;re required to calculate the time it would take for the battery to discharge to 15 watts to give you an idea of what an exponential decay would look like. I&#x27;ve plotted the power off our given battery in Watts against the time in days. We&#x27;re required to calculate the time it would take for the power to reduce to 15 watts, so plucking and P equals 15 watts. We need to sell for tea. We can move the 52 the left hand side and apply natural log on both sides. And then our right hand side would simplify to just negative t over to 50. And then from this we would say t equals Make it if vve 250 multiply but natural. Look 15 over 50 which would give us approximately 301 days, and we can see from the graph that it responds to the to the right number of these

Joshua Eastwood · Answer

So we&#x27;re giving up our open formula for a satellite, actually an isotope that&#x27;s being used our separately. But it looks like this. Then we&#x27;re asked to figure out how long sign like last days, and it needs 10 watts of power to actually focus. So what I&#x27;m gonna do is I&#x27;m gonna take this formula equal in, and then I&#x27;m going to attempt its all for tea. So I&#x27;m gonna divine by 51st. Both of these, though 10 divided by 50 is 0.2 is equal to eat, the negative be over 2 50 And then what we&#x27;re gonna do is we&#x27;re gonna take a lot of both sides. That&#x27;s gonna be long a 0.2. And when you take the lawn of E, it just simply is an inverse operation. So if your movement first writing that along with him. So that means that minus 250 lawn of 0.2 we multiply out is gonna be. And then we take your calculator and multiply minus 2 50 uh, lawn of 0.2. And again, I&#x27;m doing this on my calculator. But I would encourage you to do the same. So that gives me 400 2.4. So approximately 402 days

Linh Vu · Answer

f b ego Do rebound 100 we need to find the temperament of a condom fund. Ah, power would have to be about and the river to which you get in the end times very about on the M minus one. And here we can identify the and he echoed your 100 therefore again 100 Thames Veba 100 minus one and we get 100 times rebound off 99.

Problem

Solve the given problems by finding the appropria…

Problem 25 Easy Difficulty

Solve the given problems by finding the appropriate derivative.
The power supply $P(\text { in } W$ ) in a satellite is $P=100 e^{-0.005 t}$, where $t$ is measured in days. Find the time rate of change of power after 100 days.

Answer

$-0.303 \mathrm{W} / \mathrm{day}$

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Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus

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$-0.303 \mathrm{W} / \mathrm{day}$

Basic Technical Mathematics with Calculus

Catherine R.

Kristen K.

Michael J.

Joseph L.

Precalculus Review - Intro

Functions on the Real Line - Overview

Allyn J. Washington, Richard S. EvansBasic Technical Mathematics with Calculus

Catherine R.

Kristen K.

Michael J.

Joseph L.

Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus