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Solve the given problems by finding the appropriate derivative.The radius of curvature at a point on a curve is given by $R=\frac{\left[1+(d y / d x)^{2}\right]^{3 / 2}}{d^{2} y / d x^{2}}$A roller mechanism moves along the path defined by $y=\ln \sec x(-1.5 \mathrm{dm} \leq x \leq 1.5 \mathrm{dm}) .$ Find the radius of curva-ture of this path for $x=0.85 \mathrm{dm}$.

Calculus 1 / AB

Chapter 27

Differentiation of Transcendental Functions

Section 8

Applications

Derivatives

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So we need to find the radius of find by what it's equal to early enough can't and what's so that the intervals. 20 -1.5 DM It's less money to act and X is less than or equal to 1.5 in order to find the radius of curvature When X is equal to 0.5 0.85. Yeah, we first have to find Distressing, the second derivative of R. So to find the first derivative of dysfunction. Why is equal to Eleanor Secret facts With respect dy over DX that is equal to one of the second time she pins X time. Thanks. It's 10. The second derivative different unions and thanks The derivative of 10 access. You can square that. So now, Using Diet families one plus tan squared is equal is equal to seek. So are R is equal to C cube over. If you can square that another secret attack

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