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Welcome to numerid.
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In the current problem, we have to join the midpoints of a given isiskeler triangle and then comment on that.
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So let us draw the midpoint joining lines that are like this.
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So if i mean, say the initial triangle was a, b, c and this is p, u .r, then we will.
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Can find out certain things.
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First thing, we are telling that these all are midpoints and we know that if we join midpoints of two sides, it will be parallel to the third side.
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Okay, so this is parallel to this.
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Clearly, we then will have a number of angular properties like this angle plus this angle will be 180 and there will be many other things for example even the same way this and this will be a perfect rectangle because just the way this and this are being parallel same way this and this this will be parallel.
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This and this sides will also be parallel.
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Also, we can find that this triangle pqr and this triangle apr will be exactly equal by sss, side, side, side property.
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Why? because they also, if these two are at midpoint, then this is, this point will also be midpoint.
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Because we have found that all of these prq, pq are the midpoints.
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Now, since this ac and ab are same, okay, so we can show pq, pq is equals to pb, is equals to pa is equal to ar is equal to rc is equals to rq.
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All the sides will be equal.
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Why? because first thing, ab equals to ac.
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A .b equals to ac.
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Therefore, half of abs will also be half of ac.
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So all this ap, p, b, a, rc, all are equal...