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Solve the given problems.Sketch the graph of $y=2 \sin x+\sin 2 x(0 \leq x \leq 2 \pi) .$ Check the graph on a calculator.
Calculus 1 / AB
Chapter 27
Differentiation of Transcendental Functions
Section 4
Applications
Derivatives
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Lectures
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a. Sketch the graphs of $y…
01:15
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Graph $y=|\sin x|,-2 \pi \…
02:10
Use a graphing calculator …
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Find the solutions of the …
05:07
So let's get a good graph of sign of X first somebody graph y equals the sign of X in black here, and we'll see that, Remember? 1234 We've got pi over two pi three pi over to two pi A standard cycle is gonna go from 0 to 2 pi. It's gonna have a range from negative 1 to 1. And from graph in your unit circle points, we're gonna end up with a nice, simple graph that looks like this. And when we craft the coasts, Eakin of acts were looking for all of the reciprocal values. So in this particular case we have, it's undefined. Zero when the reciprocal of one is one, the reciprocal of negative one is negative. One. The closer I get to zero, the reciprocal will closer. It will get to infinity. So that's what Backdraft looks like. And what we have here is we're looking for all the values in which of the same, so they will always be the same when my ex value might. When my range values my Y values are one or negative one. So it's going to happen at pi over two plus every two pi n What does that mean? That means each cycle is two pi. So the graph continues to repeat over and over and over again. So puffin we started pi over two and keep rotating in either direction and could be positive or negative imagers so we can go to the right or to the left and three pi over two plus two pi n again, every cycle continuing to the right and every cycle continuing to the left. These will be all of the values in which
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The number 2 is also the smallest & first prime number (since every other even number is divisible by two).
If you write pi (to the first two decimal places of 3.14) backwards, in big, block letters it actually reads "PIE".
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