Question
Solve the given question related to graphing common functions.A parabola has the vertex form $y=3(x+1)^2$ +4 . What is the vertex form of this parabola if it's shifted 6 units to the right and 2 units down?
Step 1
The given equation is \( y = 3(x+1)^2 + 4 \). In vertex form, \( y = a(x-h)^2 + k \), the vertex is \((-h, k)\). Here, \( h = -1 \) and \( k = 4 \), so the vertex is \((-1, 4)\). Show more…
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