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Solve the inequalities in Exercises 1 to 6 .$$-15<\frac{3(x-2)}{5} \leq 0$$
Algebra
Chapter 6
Linear Inequalities
Section 4
Graphical Solution of Linear Inequalities in Two Variables
Systems of Equations and Inequalities
Campbell University
Baylor University
University of Michigan - Ann Arbor
Lectures
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to solve this inequality. We need to get rid of that six in the middle. So since this positive lists of track six from all parts that will cancel the sixth limb, it'll will have one. Minus six is a negative five. We have a mind sex or a negative X left and then three minus six is a negative three. Now we got a divide by negative one to get this X by itself. So divide everything by negative one. So when we do that, we gotta flip the inequalities. So negative five divided by negative one is five. Flip the inequality, the negative cancels and Justin X and then flip the inequality in negus three, divided by negative one is three.
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