Question
Solve the inequality and graph the solution on the real number line.. $\frac{x+12}{x+2}-3 \geq 0$
Step 1
We can do this by combining like terms. $\frac{x+12}{x+2}-3 \geq 0$ This simplifies to: $\frac{x+12-3(x+2)}{x+2} \geq 0$ Show more…
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