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Solve the initial value problem.$$4 y^{\prime \prime}-4 y^{\prime}+y=0, \quad y(0)=-1, y^{\prime}(0)=2$$

Calculus 3

Chapter 17

Second-Order Differential Equations

Section 1

Second-Order Linear Equations

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Solve the initial value pr…

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Solve the initial-value pr…

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Solve

Okay, we have times y double prime minus 4 y prime plus y equals 0 with 0 minus y prime of 0 is equal to 0 to 4 times r squared minus 4 plus movement is equal to 01 square, is equal to 0. Is equal y x? Is equal to z, 1 e of x and y t t to extant e of x y t y 0 equals c 1, which is to ponteseive to my value? Was minus 1 y prime of x is z, 1 divided by 2 oytos 2 x diary 2 plus c t divided by 2 x. T e x and y prime of 0 is divided by 2 plus c 2, which is equal to 122, is equal to pi. Divided by 2, so e y x is minus e x, divided by 2 plus 5 by 2 x x, squared.

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