00:01
In this question we'll recall about the second order ode on the form ay double pram plus by prime plus cy equal to 0 and then we can define the characteristic equation a r square plus pr plus c equal to zero then suppose that we have two complex root i 1 and 2 equal to the n -fah plus and minus beta and then we have the general solution y equal to the constant c1 e to the alpha x time cosine beta x plus c2 e to the alpha x times si beta x and in this question we're given the equation y double prime 4 y double prime plus 4 y prime prime plus 3 y equal to 0 with the initial value y0 equal to 0 y prime 0 equal to 1 here the first time we need to compute to write down the characteristic equation 4 r plus 4r plus 4r plus 3 equal to 0 using the quadratic formula r1 2 equal to the minus 4 plus a minus square root of the 16 plus the minus here we have have the 16 times 3 is equal to the 48.
01:37
This one will be the minus here, sorry, minus divided by the 2, i will be 8.
01:43
Then we get equal to the minus 4 plus and minus square root 32, divided by 8.
01:53
And then we will get, it will equal to minus 1 plus and minus.
02:00
Here we have the 16 times 2 will be squared up 2 and then dividing by the 4 so we have a 2 here.
02:11
And from here we can write this down into the form of the minus 1 over 2 plus a minus.
02:18
We have here will be the square of 2 over 2.
02:21
This one will be i, sorry about that, i here, and i here...