Question
Solve the initial-value problem.$\frac{d u}{d t}=\sqrt{t}+\frac{2}{\sqrt{t}}, \quad t>0, u(1)=5$
Step 1
This gives us: $$ \frac{d u}{d t}=t^{\frac{1}{2}}+2t^{-\frac{1}{2}}, \quad t>0 $$ Show more…
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