00:01
Problem number 67, here we're solving an initial value or a boundary condition problem for a differential equation.
00:09
Okay, so i've got a differential equation here.
00:12
What's nice about this is this can be solved by separation of variables, meaning you've got two variables here, x and t.
00:18
You can get all of the x variables on one side with d x, all of the t variables on the other side with d t, and then we can integrate both sides of this equation.
00:27
So in doing so, i can write this equation as just simply dx is equal to 1 over t squared minus 3t plus 2dt.
00:43
So now i've got all of the variables with x on the left side.
00:47
All of their variables with t are on the right side.
00:50
So now i can integrate both sides of this equation.
00:54
The left side is trivial.
00:56
The right side is where i'm going to need to do my work...