00:01
Okay, so in this problem, we have to solve the initial value problem, x prime equals 5x and x0 equals 7.
00:07
So in this case, it's an easy one, right? this is a traditional ode whereby we know that if we have x prime being x, the solution is the exponential, right, plus times the initial condition.
00:18
Since we have 5x in here, this immediately tells that x of t will be some constant times e to the 5t.
00:27
So this is the function whose derivative is itself.
00:30
Multiplied by 5, where c is a real constant in here, and taking t equals 0, we obtain e to the 0 is 1, so x of 0 is equal to c, which implies that c is simply 7.
00:48
So all in all, the solution to our initial value problem is the function 7, e to the 5t, for t in r.
00:58
Okay, and we are supposed to plot this picture.
01:04
Let's just try, you know, at zero we're going to be at seven...