00:01
Hello.
00:02
So here we have the equation.
00:03
Log base 2 of x plus 20 minus log base 2 of x plus 2 equals log base 2 of x.
00:09
Well, since we are subtracting here to logs the same base, we can rewrite this as the quotient of a single log.
00:17
So we have here, we can rewrite this as log base 2 of subtracting.
00:23
This is going to be log base 2 of x plus 20 over or divided by x plus 2.
00:32
Is then going to be equal to, well, log base 2 of x.
00:39
Okay.
00:41
Okay, so we can go ahead, rewrite that as a single log, and then we can, well, solve this for x because we know that the log property says, okay, log base 2 of something.
00:54
This must be the exponent that you raise the base to to get the argument...