00:01
Here we can use addition property of logarithm.
00:04
We know that when the bases are same, we can change addition to multiplication.
00:11
So here let's apply that rule.
00:15
Then logarithm x plus 1 times stuff inside of second logarithm x minus 1 equals 0.
00:24
And this will be logarithm x plus 1 times x minus 1.
00:29
It is x squared minus 1 equals 0.
00:33
And here we need to change it with exponential form.
00:37
The base is not written, but we know that it is 10.
00:40
It's common logaritium.
00:42
So let's change it with the exponential form.
00:47
In exponential form, stuff inside of logarithm equals base to the zero power, that is 10 to the zero power.
00:56
So x squared minus 1, 10 to 0 power is 1.
01:01
Then let's add plus 1.
01:04
Then it is x squared equals 2.
01:08
Let's take both side the square root.
01:11
Then x equals here plus minus root of 2.
01:16
And we know that for the domain of log item, we need to check our solution.
01:24
Here we have two solutions.
01:26
One of them is x equals x root of 2, and the other one is negative root of 2.
01:34
So let me write first full root of 2 in the original question...