00:01
All right guys, for this question, we are given the following data for air that is t1 is equal to 1 ,800 kelvin, and we've got m is equal to 0 .1 kg.
00:15
Then we've got p1 is equal to 4 megapascal, and then we've got n is equal to 1 .5.
00:24
Then we've got v2 is equal to 10 times of v1.
00:28
So to calculate the work, we have to first find the final pressure and final temperature.
00:37
So calculating the final temperature as p2 over p1 is equal to v2 over v1 raised to power n.
00:46
Now p2 is equal to p1 multiplied by v2 over v1 raised to power n.
00:54
Now we have p2 is equal to 400 multiplied by 1 by 10 into raise to above 1 .5 and the answer is 126 .5 kilo -pascal.
01:07
So now let's calculate the final temperature that is t2 over t1 is equal to v2 over v1, days to power n minus 1, then we note that t2 is equal to t1 into v2 over v1, raise to power n minus 1, and we have t2 is equal to 1 ,800 multiplied by 1 by 10 into raise to power 0 .5, that is equal to 569 .2 kelvin.
01:41
So the work done in the process is equal to w is equal to integral of p, dv that is p2 into v2 minus p1 into v1 divided by n minus 1 and then we have w is equal to m into r into t 2 minus t 1 divided by 1 minus n and the value of r is equal to 0 .287 kilo jowls per kg kg kelvin so guys, we have the value of w that is 0 .1 into 0 .287 multiplied by 569 .2 minus 1 ,800, and that is 1 minus 1 .5, and that is equal to 70 .64 kilojoules per kg.
02:40
And the w is equal to 70 .64 kiosso...