Problem

Solve the problems in related rates. The electric…

Problem 8 Easy Difficulty

Solve the problems in related rates.
The force $F$ (in $1 \mathrm{b}$ ) on the blade of a certain wind generator as a function of the wind velocity $v$ (in $\mathrm{ft} / \mathrm{s}$ ) is given by $F=0.0056 v^{2}$. Find $d F / d t$ if $d v / d t=0.75 \mathrm{ft} / \mathrm{s}^{2}$ when $v=28 \mathrm{ft} / \mathrm{s}$.

Answer

Related Courses

Calculus 1 / AB

Basic Technical Mathematics with Calculus

Chapter 24

Applications of the Derivative

Section 4

Related Rates

Discussion

You must be signed in to discuss.

Top Calculus 1 / AB Educators

Watch More Solved Questions in Chapter 24

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Video Transcript

all right. Third time's the charm of this case. I'm going to get at this time. Bear with me. All right. Force varies jointly with the area of the surface. Um, and the velocity squared. So there's our equation service area in that area. Um, were given that the forces £50 when the area of the object, the surface area of it is 1/2 a square foot, not very big, and its velocity is 40. All right, Well, first of all, 40 squared is 1600 than half of that would be 800 so 50 equals 800 k If we divide both sides by 850 divided by 800 that's 0.6 to 5. So there's our constant variation. So our force is that 0.6 to 5. Sometimes the surface area of victims of last squared now were given a bigger object instead of 1/2 a square foot, it's two square feet and faster winds instead of 40 80 which is like hurricane force winds. Giving him 40 was a lot 80. Well, you don't feel that very often. All right, so I'm gonna take that 800.625 which is still in my calculator. Multiply it by two and then multiply it by 80 squared. And that gives me £800. Um, force.

Get More Help with this Textbook

Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus

View More Answers From This Book

Find Another Textbook

Problem

Solve the problems in related rates. The electric…

Problem 8 Easy Difficulty

Answer

Related Courses

Basic Technical Mathematics with Calculus

Related Topics

Discussion

Top Calculus 1 / AB Educators

Anna Marie V.

Heather Z.

Kayleah T.

Samuel H.

Calculus 1 / AB Courses

Precalculus Review - Intro

Functions on the Real Line - Overview

Recommended Videos

Watch More Solved Questions in Chapter 24

Video Transcript

Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus

Anna Marie V.

Heather Z.

Kayleah T.

Samuel H.

Precalculus Review - Intro

Functions on the Real Line - Overview

Basic Technical Mathematics with Calculus

Anna Marie V.

Heather Z.

Kayleah T.

Samuel H.

Precalculus Review - Intro

Functions on the Real Line - Overview

Allyn J. Washington, Richard S. EvansBasic Technical Mathematics with Calculus

Anna Marie V.

Heather Z.

Kayleah T.

Samuel H.

Precalculus Review - Intro

Functions on the Real Line - Overview

Allyn J. Washington, Richard S. Evans

Basic Technical Mathematics with Calculus