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Solve the problems in related rates.The kinetic energy $K$ (in $J$ ) of an object is given by $K=\frac{1}{2} m v^{2}$, where $m$ is the mass (in $\mathrm{kg}$ ) of the object and $v$ is its velocity. If a $250-\mathrm{kg}$ wrecking ball accelerates at $5.00 \mathrm{m} / \mathrm{s}^{2}$, how fast is the kinetic energy changing when $v=30.0 \mathrm{m} / \mathrm{s} ?$ (Hint: $\operatorname{acceleration}=\frac{d v}{d t}.$)
Calculus 1 / AB
Chapter 24
Applications of the Derivative
Section 4
Related Rates
Derivatives
Campbell University
Oregon State University
Baylor University
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We're given the scenario that if he is to 50 and Emma's five, what will the velocity be? And so we're gonna use that information, plug it into the formula and solve. So we're gonna replace E with the number 2 50 and we're gonna replace the M with the number five and going to try and solve for B squared. So first things first, you have to 50 half of five is 2.52 pi b squared right both side by 2.5. And when you do that to get the visa, it alone on the right answer to drop by 2.5 ends up being 100 birth where Ruth sides of our velocity is gonna end up being 10. So meters earns getting an answer.
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