Question
Solve the system$$\begin{aligned}& x+2 y+2 z=5 \\& 2 x+y+2 z=7 \\& 2 x+2 y+z=3\end{aligned}$$in integers modulo 13 by doing mod 13 arithmetic by hand. Check your solution.
Step 1
The system can be represented as: \[ \begin{bmatrix} 1 & 2 & 2 \\ 2 & 1 & 2 \\ 2 & 2 & 1 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 5 \\ 7 \\ 3 \end{bmatrix} \] Step 2: We will perform row operations to reduce the matrix to row Show more…
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