00:01
We need to solve the system of equations.
00:03
Here we are trying to solve this.
00:05
So let us make our matrix first.
00:09
In the matrix, the first column is coefficient of x, then coefficient of y, then coefficient of z.
00:18
And the last is constant terms.
00:22
So our matrix will be 2 minus 4 minus 1, 2, 1, 1, minus 3.
00:32
10 minus 1 minus 7 8 and 2.
00:40
This is our matrix.
00:43
To solve we need identity matrix for first three columns and the last column will give us the value of x, y and z.
00:56
So to start, let us swap the first two rows r1 and r2 so that we have a 1 here.
01:06
So we'll get 1, 1, minus 3, 10, 2, minus 4, minus 1, 2 minus 1, minus 7, 8 and 2.
01:25
This is our new matrix.
01:28
Then next we need 0 at these two places.
01:32
So let us perform row 2 is row 2 minus 2 times row 1 and row 3 is row 3 plus row 1...