00:02
So to solve the system of equations using elimination, well, if we add our first equation plus our second equation, what we would get is this x minus 2x.
00:13
So we'd get negative x and then positive 2y minus 6x.
00:18
So we'd have minus 4y.
00:19
And then negative z plus z gives us 0.
00:22
And then this is equal to negative 3 plus 4.
00:25
So this is equal to 1.
00:27
And so now if we want to get rid of z in our third equation, well, let's say we.
00:32
We multiply 2 times our second equation, so 2 times our second equation, and then add it to our 3rd equation.
00:40
So this would give us negative 4x, negative 4x, plus 5x, so we'd have x, and then negative 12 minus 4.
00:49
So negative 12 minus, or negative 12 plus 4, rather...