00:01
Here on this problem, we want to solve this system of equations using substitution.
00:05
Now, y is equal 6 .8x plus 2 .3.
00:09
And so i'm going to substitute that in there and that bottom equation for y.
00:15
And so this gives us 6 .8x plus 2 .3 equals negative 4 .1x plus 56 .8.
00:27
And so now we have this equation in red that we can solve.
00:32
So to do this, i'm going to add 4 .1x to both sides, just taking my xes over to the left.
00:40
Subtract 2 .3 on each side, just taking my numbers over to the right.
00:49
So here on the right, 56 .8 minus 2 .3, that's 54 .5.
00:57
Here on the left, 6 .8x plus 4 .1x.
01:02
That's 10 .9x...