The Law of Sines states that $\frac{a}{\sin A} = \frac{c}{\sin C}$. Plugging in the given values, we have $\frac{17.2}{\sin 126.5^{\circ}} = \frac{13.5}{\sin C}$. Solving for $\sin C$, we get $\sin C = \frac{13.5}{17.2} \cdot \sin 126.5^{\circ}$. Taking the
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