Question
Solved Problem $7-4$ showed that the debromination of $(R, R)-2,3$ -dibromobutane gives cis2-butene. Draw the same reaction using the $(S, S)$ enantiomer and show that it gives the same diastereomer of the product.
Step 1
First, we need to draw the (S, S)-2,3-dibromobutane molecule. Remember that (S, S) means that both chiral centers have the S configuration. Show more…
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Key Concepts
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Draw the products formed when both cis- and trans-2-butene are treated with $4Os0_4$, followed by hydrolysis with $NaHS0_3$ $+ H_20$. Explain how these reactions illustrate that syn dihydroxylation is stereospecific.
Oxidation and Reduction
Dihydroxylation
Hydroxylation of cis-2-butene with OsO_y yields a different product than hydroxylation of trans-2-butene. Draw the structure, show the stereochemistry of each product, and explain the difference between them.
a. Draw the product or products that will be obtained from the reaction of cis -2-butene and trans-2-butene with each of the following reagents. If a product can exist as stereoisomers, show which stereoisomers are formed. 1. $\mathrm{HCI}$ 2. $\mathrm{BH}_{3} / \mathrm{THF}$, followed by $\mathrm{HO}^{-}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{H}_{2} \mathrm{O}$ 3. a peroxyacid 4. $\mathrm{Br}_{2}$ in $\mathrm{CH}_{2} \mathrm{Cl}_{2}$ 5. $\mathrm{Br}_{2}+\mathrm{H}_{2} \mathrm{O}$ 6. $\mathrm{H}_{2}+\mathrm{Pd} / \mathrm{C}$ 7. $\mathrm{H}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{SO}_{4}$ 8. $\mathrm{CH}_{3} \mathrm{OH}+\mathrm{H}_{2} \mathrm{SO}_{4}$
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