00:01
In this problem we are trying to solve the linear programming problem.
00:05
So this is y xx and this is xx.
00:10
We need to graph our constraints first.
00:13
So this is x is greater than equal to 0 and this is y is greater than equal to 0.
00:22
Then next we have x plus 4 y is equal to 60.
00:27
We need x and y intercepts to graph our equation so the x intercept at x intercept y is 0 so we have x plus 0 is equal to 60 so x intercept is 60 60 comma 0 then at y intercept x is 0 so 0 plus 4 y is equal to 60 so y is equal to 15 and r y intercept is 0 and if we join these two points we get our graph and we have x plus 4 y less than equal to 60 so less than means shade is downwards this is our shade then we have 3x plus 2 y is greater than equal to 48.
01:35
So again we need x and y intercept so 3x is equal to 48 gives x is equal to 16.
01:44
So the x intercept is 16.
01:48
0 and 2 y is equal to 48 gives y is equal to 24 and y intercept is 0 4 .24.
02:01
Now we join these two points and this is our graph but we need shade as well and we have 3x plus 2y is greater than equal to 48 greater than means we have shade upwards so the common region is this region.
02:28
The triangle this is the common region in the shape.
02:34
We also need the point of intersection.
02:38
So the equations we have are x plus 4y is equal to 60 and 3x plus 2y is equal to 48...