This gives us $2A$ and $4B$:
$2A = 2\left[\begin{array}{rr}-2 & -1 \\ 1 & 0 \\ 3 & -4\end{array}\right] = \left[\begin{array}{rr}-4 & -2 \\ 2 & 0 \\ 6 & -8\end{array}\right]$
$4B = 4\left[\begin{array}{rr}0 & 3 \\ 2 & 0 \\ -4 & -1\end{array}\right] =
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