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Solving a System by Substitution In Exercises$7-14,$ solve the system by the method of substitution.Check your solution(s) graphically.$$\left\{\begin{aligned} x+y &=0 \\ x^{3}-5 x-y &=0 \end{aligned}\right.$$
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This gives us: $$x^{3}-5x-(-x)=0$$ which simplifies to: $$x^{3}-4x=0$$ Show more…
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