00:01
Here, a system of equations has been given to us.
00:04
The first equation is 1 upon 2x plus 3 upon 4 y equal to 10.
00:12
And the second equation is given to us as 3 upon 4 x minus y equal to 4.
00:20
So now we have to use the substitution method to find out the solution of the system of equations.
00:25
So over here by using the substitution method what i'm going to do is i'll just pick up equation two.
00:33
So from equation two i'm going to find out the value of y in terms of x.
00:38
So y will be equal to 3 upon 4 x minus 4.
00:43
Now i'm going to substitute this value of y in equation 1.
00:49
So substitute the value of y in equation 1.
00:54
So we'll be getting 1 upon 2x plus 3 upon 4 times 3 upon 4 x minus 4 equal to 10.
01:05
Just solve this equation, simplify this further.
01:08
So you'll be getting 1 .2x plus 9 upon 16x...