00:01
So in this problem, the reason for the observation is because if we take a closer look at these complexes, then this is what would happen if they were placed in aqueous solution.
00:30
So for the first one, we have six of the amine ligands.
00:38
And you can see here that we end up with four chloride ions and no chloral ligands attached to the metal complex here.
00:54
But if we have five amine ligands, we can see that one of the chlorines is going to end up being a chloral ligand and not a chloride.
01:11
Ion.
01:13
So then when this associates in the solution, we'll end up with three chloride ions.
01:25
So if we look back at the chart that we're given in the original text, you can see that if we were to add the silver ion, it would make sense that we would only be able to precipitate the chloride ion and not the chloral ligand that's still attached to the metal complex.
01:49
So these equations basically show us that the number of chloride perform a unit precipitated by silver is going to be going down with each of these compounds.
02:17
So i'll also look at the explanation will lead us to conclude that metal ions have two different kinds of valence.
02:29
So they have a primary valence, which is their oxidation state and the corresponds to the positive charge on the ion.
02:36
So in this case, the primary valence in the platinum is four...