00:01
The average service time from the question is equal to 2 .78 minutes.
00:07
If you assume that the service time follows an exponential distribution.
00:17
For an exponential distribution with the mean of 2 .78, the probability density function, f of x or p of x, is equal to 1 minus the mean, which is 2 .78, times e, raised to the power negative 1 over 2 .78 x.
00:42
So for the first question we are to find the probability that service time is less than two minutes.
00:50
This can be written at the probability that x is less than or equal to 2.
00:58
Where we are computing the probability that x is less than or equal to a certain value, which is x0, it is equal to 1 minus e raised to the power negative x not divided by the main.
01:14
So we have 1 minus e raised to the power our x not is 2 divided by the mean which is 2 .78 and this is equal to 1 minus 0 .4870 and this is equal to 0 .513.
01:42
For the next question we are to find the probability that service time is more than 5 minutes and we can represent this as the probability that x is greater than or equal to 5.
02:00
To compute this probability, we need to integrate the function 1 over 2 .78 exponent negative 1 over 2 .78 x dx from 5 to infinity.
02:19
The integral of this function is equal to negative e raised to the power negative 1 over 2 .78 x as we integrate from 5 to infinity...