Question
Specific gravity of a body is numerically equal to:(a) weight of the body in air(b) weight of the body in water(c) relative density of the body(d) density of body in water
Step 1
Mathematically, it can be represented as: \[ Specific Gravity = \frac{Weight_{air}}{Weight_{water}} \] Show more…
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The force of buoyancy on an immersed body is: (a) due to weight of the body (b) due to the pressure difference between upper surface and lower surface of the body (c) due to atmospheric pressure (d) both (a) and (c) are correct
The weight of a body in water is one-third of its weight in air. The density of the body is (A) $0.5 \mathrm{gm} / \mathrm{cm}^{3}$ (B) $1.5 \mathrm{gm} / \mathrm{cm}^{3}$ (C) $2.5 \mathrm{gm} / \mathrm{cm}^{3}$ (D) $3.5 \mathrm{gm} / \mathrm{cm}^{3}$
The relative density of the material of a body is the ratio of its weight in air and the loss of its weight in water. By using a spring balance, the weight of the body in air is measured to be $5.00 \pm 0.05 \mathrm{~N}$. The weight of the body in water is measured to be $4.00 \pm 0.05 \mathrm{~N}$. Then, the maximum possible percentage error in relative density is (a) $11 \%$ (b) 1096 (c) $9 \%_{6}$ (d) $7 \%$
Units and Measurements
Round 1
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