00:01
For this problem, to be able to solve for n, we can use the least common denominator and combining like terms.
00:09
To start, we're going to see if there's any exclusion since the variables are in the denominator.
00:16
So in the first one, it's 1 over n.
00:19
And in the denominator, it can never equal 0.
00:22
So n cannot equal 0.
00:28
So we'll keep this in mind with solving.
00:30
The second denominator is n plus 1, which cannot equal 0.
00:38
So if we subtract a 1 to the right side of the problem, n cannot equal negative 1.
00:46
So these two will be excluded from the answers.
00:55
To start this problem, we will need to get the least common denominator.
01:00
We notice on the right side of this equation that there is an n, times n plus 1 and those are the two that are given on the left side so we will multiply the first 1 over n plus 1 over n plus 1 the 1 over n plus 1 will be multiplied by n over n over n over n times n plus 1 plus n over n times n plus 1.
02:02
And this will equal the original negative 1 over n times n plus 1, since it is already in its least common denominator.
02:16
Now that the denominators are all the same, we are able to get them to one side to be able to combine like terms...