00:01
For this problem, to be able to solve for t, you will need to use the least common denominator.
00:08
On the left side of the equation, you are given 16 the denominator.
00:12
While on the right side, you're only given 3t.
00:15
So i started out by multiplying the 3t times 2, so i can get the same denominators.
00:23
So that will equal 7 over 6t equals 2 plus 2 plus.
00:40
10 over 6 t.
00:47
From here, i saw that since both of the t's were in the denominator, i know that t cannot equal 0.
00:59
The next step i did was to get the 2 onto the last side of the equation.
01:06
So i subtracted 2, and that will be crossed out because it'll equal 0.
01:18
So now it will be 7 over 6 t minus 2 equals 10 over 6t.
01:41
Now i am able to subtract the 7 over 6t since they are like terms.
01:50
On this left side, it will cancel out to 0, so i'll cross that out...