00:01
This question regards the zeman effect or zeman splitting.
00:05
And it asks if we have a gas that is undergoing a p to s transition that emits a certain wavelength plus or minus a little bit, resulting in a three -band wavelength.
00:21
This asks what the magnitude of the external magnetic field is.
00:27
Zeman splitting says that energy levels of electrons split and enter new discrete energy levels under the influence of an external magnetic field.
00:40
So given our initial wavelength of 575 .05 nanometers, that splitting occurs and causes two new wavelengths to come about that are 0 .0462 nanometers away.
00:57
The question again asks, what is the strength of the magnetic field? so to do this, first we need to understand what the energy is of a single photon, and that is going to equal hc over lambda.
01:17
Now, we can see that we can get a few different energies from this problem.
01:22
We have our initial wavelength, and then we have an excited state and a slightly disexcited state.
01:28
The longer wavelength will be more energetic, and that's the one we're going to use to solve the problem, but you could use the other one as well.
01:38
Our initial energy, which we will label ei, using planx constant, which is 4 .14 times 10 to the minus 15 ev and the speed of light, divided by lambda, which is just going to be r575 .05 .05 nanometers.
01:59
If we plug all of that in, we end up getting 2 .1981 electron volts.
02:09
That is the energy of our ground, if you will, state photon.
02:16
The unexcited photon.
02:19
Now, our final energy, we can choose either of the different bands.
02:26
We're going to choose, in this case, the higher wavelength band.
02:29
So adding 0 .0462.
02:32
If we do this, we have a slightly higher wavelength, which ends up being 575.
02:40
575 .0962.
02:48
And if we do the same calculation with h and c, we end up getting 2 .196 electron volts...