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Averell H.
Carnegie Mellon University

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70

Problem 58 Hard Difficulty

Spiraling up. It is common to see birds of prey rising upward on thermals. The paths they take may be spiral-like. You can model the spiral motion as uniform circular motion combined with a constant upward velocity. Assume a bird completes a circle of radius 8.00 $\mathrm{m}$ every 5.00 $\mathrm{s}$ and rises vertically at a rate of 3.00 $\mathrm{m} / \mathrm{s} .$ Determine: (a) the speed of the birc relative to the ground; (b) the bird's acceleration (magnitude) and direction); and (c) the angle between the bird's velocity vector and the horizontal.

Answer

a) 8.11 $\mathrm{m} / \mathrm{s}$
b) 9.48 $\mathrm{m} / \mathrm{s}^{2}$
c) $\left[21.7^{\circ}\right]$

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Video Transcript

So we have a bird with centripetal with uniform circular motion. However, it is also moving in the positive. Why direction? So we have a radius of eight cent rather eight meters, so it's flying around in a circle with a radius of eight meters and it makes one revolution every five seconds. So as a period essentially of five seconds, it also has a V y of three ministers. Second, because that is as it is, moving in a certain as the birds moving in a circle. It is also moving up so we can save these of acts simply equals the circumference of this 18 year, 88 meter radius circle divided by the period. So this would be two pi r divided by t and this would be to pi times eight, divided by five and this is giving us 10.5 meters per second now to find the magnitude of the velocity vector, we can say that the magnitude is going to be three squared plus 10.5 squared all 2 1/2 power and this is giving us 10 point for nine meters per second. So this would be the velocity vector The linear velocity vector of the bird. Now for part B is asking us for the radio acceleration or so we can say that a and the wind direction is going to be zero me after second. Because thie why thie velocity and the Y direction is going to be constant. And we can say that the radio exploration was in triple exploration. In this case would be the X squared divided by our and this would be 10.5 squared, divided by eight. And this is giving us 12.63 meters per second squared now. It wants us to find the angle of the linear velocity with respect to the horizontal. So for part, see, we simply say that Fada Ah, it's going to be ableto are 10 of the wine component so three divided by the ex component 10.5 so this would be equal to 16.6 degrees. And then again, this is for this is going to be above the horizontal direction of the velocity factor with respect to the horizontal. And that is the end of the solution. Thank you for watching

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Hugh D. Young

College Physics

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