Question
$$\sqrt{2 k^{2}+17}-x=0$$If $k>0$ and $x=7$ in the equation above, what is thevalue of $k ?$\begin{equation}\begin{array}{l}{\text { A) } 2} \\ {\text { B) } 3} \\ {\text { C) } 4} \\ {\text { D) } 5}\end{array}\end{equation}
Step 1
Step 1: Substitute $x=7$ into the equation, we get \begin{equation} \sqrt{2 k^{2}+17}-7=0 \end{equation} Show more…
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