Square roots and the solvability of quadratic equations in $\mathbb{C}$
Let $c=a+\mathrm{i} b \neq 0$ be a given complex number. By splitting it into its real and imaginary part show that there are exactly two complex numbers $z_{1}$ and $z_{2}$ such that
$$
z_{1}^{2}=z_{2}^{2}=c . \text { One has } z_{2}=-z_{1}
$$
$\left(z_{1}\right.$ and $z_{2}$ are called the square roots of $c$ ) For example, determine the square roots of
$$
5+7 \mathrm{i}, \quad \text { and } \quad \sqrt{2}+\mathrm{i} \sqrt{2}
$$
Use also polar coordinates for this exercise. Furthermore, show that a quadratic equation
$$
z^{2}+\alpha z+\beta=0, \quad \alpha, \beta \in \mathbb{C} \text { arbitrary }
$$
always has at most two solutions $z_{1}, z_{2} \in \mathrm{C}$.