Square roots. In this problem, we'll see that it is easy to compute square roots modulo a prime $p$ with $p \equiv 3(\bmod 4)$
(a) Suppose $p \equiv 3(\bmod 4) .$ Show that $(p+1) / 4$ is an integer.
(b) We say $x$ is a square root of $a$ modulo $p$ if $a \equiv x^{2}(\bmod p) .$ Show that if $p \equiv 3(\bmod 4)$ and if $a$ has a square root modulo $p,$ then $a^{(p+1) / 4}$ is such a square root.