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ssm A $1380-\mathrm{kg}$ car is moving due east with an initial speed of 27.0 $\mathrm{m} / \mathrm{s}$ . After 8.00 $\mathrm{s}$ the car has slowed down to 17.0 $\mathrm{m} / \mathrm{s}$ . Find the magnitude and direction of the net force that produces the deceleration.

1730 $\mathrm{N}$

west

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Rutgers, The State University of New Jersey

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University of Winnipeg

to sum of the squares, and we have to begin by discovering what is the deceleration off the car. For that, we can use the definition off acceleration, which is a variation velocity divided by the time it takes. The variation in velocity is given by the final velocity, minus the initial velocity and the time it takes eight seconds. Then we see that we have minor stand divided by eight and easiest the deceleration off the car. Now we can use Newton's second law discover what is the force that is producing these deceleration? Using Newton's second law in these access, we have the following in that force, acting in the car. Is he close to the mask off the car times its acceleration so and that force acting on the car is equals to 100,380 times my understand divided by eight. And these results in the net force off approximately minus 1730 Newtons, then the magnitude off the force is 1730 New terms on this force is pointing to the West, so it's pointing in this direction these eastern that force acting on the car that is producing its deceleration

Brazilian Center for Research in Physics